**Quadratic Equations Solving By Factorising GCSE Maths**

Click here to see ALL problems on Quadratic Equations Question 276999 : Put the equation 5x^2-10x-2 in turning point form a(x-h)^2+k, by completing the square. Answer by jim_thompson5910(34749) ( …... L.O.S. and Turning Point: The big advantage of Complete the Square form is that you can instantly read from the equation the Line of Symmetry and the Turning Point.

**Quadratic Inequalities Equations And Inequalities Siyavula**

Step 3: Find the turning point. we have both our x intercepts we know that the x coordinate of the turning point is exactly halfway between these. Once we have the x-coordinate, we can substitute this into our equation to find the y –coordinate.... Turning point is just the vertex of the equation, or where the parabola change direction . you can solve this by factor the equation y=x^2-2x-3 The factor form is (x-3)(x+1)

**Quadratic Equations Solving By Factorising GCSE Maths**

Turning point is just the vertex of the equation, or where the parabola change direction . you can solve this by factor the equation y=x^2-2x-3 The factor form is (x-3)(x+1)... Quadratic inequalities can be of the following forms: We can find the answer graphically by seeing where the graph lies above or below the -axis. From the standard form, , and therefore the graph is a “smile” and has a minimum turning point. From the factorised form, , we know the -intercepts are and . The graph is above or on the -axis for or . Write the final answer and represent on

**Quadratic Functions How do you sketch a quadratic curve 1**

Turning point is just the vertex of the equation, or where the parabola change direction . you can solve this by factor the equation y=x^2-2x-3 The factor form is (x-3)(x+1)... And if I have an upward opening parabola, the vertex is going to be the minimum point. If I had a downward opening parabola, then the vertex would be the maximum point. So I'm really trying to find the x value. I don't know actually where this does intersect the x-axis or if it does it all. But I want to find …

## How To Find Turning Point In Parabola By Factorise

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- How do you graph the parabola 3x^2+18x+21 using vertex
- Quadratic Functions How do you sketch a quadratic curve 1
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## How To Find Turning Point In Parabola By Factorise

### the nature and coordinates of the turning point y-intercept (ie where the parabola cuts the y-axis) Look at the National 5 completing the square section before continuing.

- Do that by choosing some other point on the parabola (not the vertex) and substitute its coordinates into equation 2. You can then work out the value of ‘a’ and complete your equation. You can then work out the value of ‘a’ and complete your equation.
- 25/11/2012 · The equation is: x^2 + 4x I need to know how to find: x-intercept: don't know how to factorise using b^2 - 4ac: i don't know what the c value is since it's not in ax^2 + bx + c format (the b^2 - 4ac is of quadratic equation to see how many solutions there are. e.g. if you substitute all the... show more The equation is: x^2 + 4x
- c) Find the equation of the parabola with turning point S. 2 44) The diagram shows the path of a small rocket which is fired into the air. (The height, h metres, of …
- 2/09/2010 · If you want to find the turning points, you got to differentiate (don't know if you've done that) with respect to x and make that equal 0. then substitute that back into the original equation and get the y co-ordinate....that'l give you your turning point(s).

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